Segment Tree Build II 439
Question
The structure of Segment Tree is a binary tree which each node has two attributes start and end denote an segment / interval.
start and end are both integers, they should be assigned in following rules:
The root's start and end is given by build method.
The left child of node A has start=A.left, end=(A.left + A.right) / 2.
The right child of node A has start=(A.left + A.right) / 2 + 1, end=A.right.
if start equals to end, there will be no children for this node.
Implement a build method with a given array, so that we can create a corresponding segment tree with every node value represent the corresponding interval max value in the array, return the root of this segment tree.
Example
Given [3,2,1,4]. The segment tree will be:
[0, 3] (max = 4)
/ \
[0, 1] (max = 3) [2, 3] (max = 4)
/ \ / \
[0, 0] (max = 3) [1, 1] (max = 2) [2, 2] (max = 1) [3, 3] (max = 4)
Solution
这题和I没有任何区别,只是多带一个属性max而已。
代码如下:
/**
* Definition of SegmentTreeNode:
* public class SegmentTreeNode {
* public int start, end, max;
* public SegmentTreeNode left, right;
* public SegmentTreeNode(int start, int end, int max) {
* this.start = start;
* this.end = end;
* this.max = max
* this.left = this.right = null;
* }
* }
*/
public class Solution {
/**
*@param A: a list of integer
*@return: The root of Segment Tree
*/
public SegmentTreeNode build(int[] A) {
// write your code here
if(A == null || A.length == 0){
return null;
}
return buildHelper(A, 0, A.length - 1);
}
private SegmentTreeNode buildHelper(int[] A, int start, int end){
if(start == end){
return new SegmentTreeNode(start, end, A[start]);
}
int mid = (start + end) / 2;
SegmentTreeNode root = new SegmentTreeNode(start, end, 0);
SegmentTreeNode left = buildHelper(A, start, mid);
SegmentTreeNode right = buildHelper(A, mid + 1, end);
root.left = left;
root.right = right;
root.max = Math.max(left.max, right.max);
return root;
}
}